Is the reciprocal of $\cfrac {-(2x-1)}{2}$

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$\cfrac{-2}{(2x-1)}$?

I want to see if I'm not forgetting reciprocals. And that I'm correct and not misremembering.

It's the negative in front of the parentheses that's throwing me off.

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The definition of reciprocal is, "the reciprocal of a number $ u $ is a number $ v $ with the property that $ u \cdot v = 1 $." So if $ u = \frac{-(2x-1)}{2} $, then does your proposed $ v = \frac{-2}{2x-1} $ satisfy this definition? Try multiplying it out and decide for yourself if it does.

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The reciprocal of a fraction is simply found by swapping the denominator with the numerator, and also by swapping the numerator for the denominator. eg the reciprocal of
$$\frac{a}{b}=\frac{b}{a}$$