Is the sequence $s_j = \sum_{k=0}^{k=j}e^{ik^2}$ bounded?

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Let

$$s_n = \sum_{k=0}^{n}e^{ik^2}$$

where $i$ is the imaginary number. Is the sequence $s_n$ bounded in the complex plane ?

I have considered expanding the function $e^{z}$ at $z = ik^2$ which is in fact

$$e^{ik^{2}} = \sum_{j=0}^{\infty}{\frac{i^{j}k^{2j}}{j!}}$$

so that

\begin{align} s_n &= \sum_{k=0}^{n} \sum_{j=0}^{\infty} {\frac{i^{j}k^{2j}}{j!}} \\ &= \sum_{j=0}^{\infty} {\frac{i^jp_{2j}(n)}{j!}} \end{align}

where $p_{2j}(x) = 0^{2j}+1^{2j}+... +x^{2j}$. How can I proceed from here?