Is there a formula for calculating $n^.5$? If so, what is it?

Question

I keep getting questions like $4^.6$, and likewise - since nothing online has helped I've reverted to remembering, which is not very good.
So, is there a way to calculate this with a formula?
The only logical way I can think of is: Take $4^.6$, for example. In this equation it would be $4*(4*0.6)$. With my formula, I get $9.6$; but the real answer is $2.29739671$.

Answer 1

$$x^{ab}=(x^a)^b$$ holds for every real number $x$. So to calculate $x^{0.6}$ you can use $(x^6)^{1/10}=\sqrt[10]{x^6}$.

Answer 2

$e^{.6∗ln(4)}$

or

$exp(0.6∗log(4))$

Any scientific calculator must have $log$ and $exp$ functions.

See comments above.