Well known Faulhaber's formula is stated as
$$\sum _{k=1}^{n}k^{p}=\frac{1}{p+1}\sum _{j=0}^{p}{p+1 \choose j}B_{j}n^{p+1-j}$$
But is there any formula which holds for power sum of the form
$$\sum_{k=s}^{n}k^{p}, \quad s\in\mathbb{Z}?$$
Well known Faulhaber's formula is stated as
$$\sum _{k=1}^{n}k^{p}=\frac{1}{p+1}\sum _{j=0}^{p}{p+1 \choose j}B_{j}n^{p+1-j}$$
But is there any formula which holds for power sum of the form
$$\sum_{k=s}^{n}k^{p}, \quad s\in\mathbb{Z}?$$
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