I'm no math wiz here, but I have a question that I can't wrap my head around. In fact, I don't even know how I would even go about asking the question properly. Is there an alternative to using 0 as a placeholder?
When writing out numbers, 10 doesn't have it's own symbol. So rather we use 1 and 0(the placeholder) to represent 10. Is there a better method than using 0 or keep from going into double digits with the number 10?
If I'm understanding your question correctly:
It's important to remember that the number of digits a number has is only dependent on what base I'm writing the number in. We typically write things in base-$10$. That is, each "slot" can go from $0$ to $9$ before we add another "slot".
However, what if I write $10_{10}$ in base-$2$? I have $1010_2$ (count up only allowing each "slot" to get to $1$ before a new "slot" is added. You'll see where $1010_2$ comes from). In this way of counting, for any even number I'm going to be using $0$ as a "placeholder".
So, my point: you could make $11_{10}$ the fist double digit double if you wanted. Just come up with another symbol to represent $10_{10}$ and then begin writing everything in base-$11$. Whenever we use a "placeholder" or go into more digits is completely dependent on the base, so you can have the first occurrence of $0$ as a "placeholder" occur whenever you want. I hope I helped, because at least I think this is what you were asking.