Let $R$ be a UFD.
Let $u$ be a unit in $R$ and $p$ be a prime element of $R$.
Is it possible that $p|u$?
If $u$ is a unit, and $a|u$, it follows immediately that $a$ is also a unit. By definition, a unit is not prime.
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If $u$ is a unit, and $a|u$, it follows immediately that $a$ is also a unit. By definition, a unit is not prime.