Is this a valid analytic continuation of ζ(s) for 0 < Re(s) < 1?

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Given $\zeta(s) = 1^{-s} + 2^{-s} + 3^{-s}...$

$2^{-s}\zeta(s) = 2^{-s} + 4^{-s} + 6^{-s}...$

$\zeta(s)(1-2^{1-s})=1^{-s} - 2^{-s} + 3^{-s} - 4^{-s}...$ which converges for $0 < \Re(s) < 1$.

Is it therefore valid to calculate the output of this convergent series and use it to find values of $\zeta(s)$ in the range $0 < \Re(s) < 1$? If so then is this valid for $\zeta(0)$ also?

Thanks for any help! It will be much appreciated!