Is this negation correct for this statement?

42 Views Asked by At

¬(for all n in N, there exists m in N, g(m,n))

equivalent to:

there exists n in N, for all m in N, ¬g(m,n)

Is that correct?

Thanks!

1

There are 1 best solutions below

2
On

Indeed, that's correct. $$\lnot( \forall n \in \mathbb N, \exists m \in \mathbb N, g(m, n))\equiv \exists n \in \mathbb N, \forall m \in \mathbb N, \lnot g(m,n)$$