Find the area of the region bounded by: $$r=5\cos(10\theta),~~~~~ 0 \leq \theta \leq 2\pi$$
When I did this, I got $\frac{1}{2\sin(20\pi)}-\frac{1}{2\sin(0)}$ getting $0$, is this correct?
2026-04-07 03:15:56.1775531756
Is this polar equation correct?
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$$ \int_{-\pi/20} ^ {\pi/20} \dfrac12 r^2 d \theta$$
is area of each of 20 rose petals.