Is this problem wrong? I keep getting $y = ±(\sqrt{c-x^4})/x$ which is not possible as $x = 0$ and $y = 2$. Am I wrong?

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Find the particular solution that satisfies the initial condition: Differential Equation:

$$(2x^2+y^2)dx+xydy=0$$

Initial Condition:

$$y(0) = 2$$

I solved it and got

$$y = ±(\sqrt{c-x^4})/x$$

which is undefined for $x = 0$.