Since $u(t)=1$ for $t>0$ and $0$ otherwise, this means that $u(t)=u(2t)$ for all $t$. Also, they both have identical graphs.
But when obtaining the derivative of both of these functions they give different results. $$\frac{du(t)}{dt} = \delta(t)$$ $$\frac{du(2t)}{dt} = 2\delta(2t)$$ Where the second derivative is obtained using the chain rule.
So does this mean that $u(t)\neq u(2t)$? or the second derivative is wrong?
Hint
We want derivative in the sense of distributions. So to check equality, you need to check equality in the sense of distributions. What distribution is $2 \delta(2t)$? That is, if $\varphi$ is a test function, what is $\langle 2\delta(2t), \varphi\rangle$? Is that the same distribution as $\delta(t)$? Answer: Yes.