Modulus 10
There are $\phi(10)=4$ characters modulo $10$.
Note that $χ$ is wholly determined by $\chi(3)$, since $3$ generates the group of units modulo $10$.
I can imagine that $\chi_2$ or $\chi_4$ generate $\chi$, by a certain kind of multiplication. But $3$? Is Wiki wrong? Maybe they started the table with $0$ once ago...

You're misunderstanding: the values of a Dirichlet character $\chi(n)$ for any $n$ are determined by $\chi(3)$, because $3$ is a generator of $(\mathbb{Z}/10\mathbb{Z})^\times$.
It is also true that the collection of Dirichlet characters modulo $m$ forms a group under (pointwise) multiplication, which in fact is isomorphic to $(\mathbb{Z}/m\mathbb{Z})^\times$. When $m=10$, we have $(\mathbb{Z}/10\mathbb{Z})^\times\cong\mathbb{Z}/4\mathbb{Z}$ and the characters listed in the table as $\chi_2$ and $\chi_4$ are generators.