Let $R_1$, $R_2$ $∈ R(X)$ be equivalence relations on $X$. Define $R_1$ and $R_2$ to be isomorphic if there exists a bijection $f : X → X$ such that the following holds:
For all $y$, $z ∈ X : (y, z) ∈$ $R_1$ if and only if $(f(y), f(z)) ∈$ $R_2$.
$(a)$ Define what it means for two partitions $P_1$, $P_2$ $∈ P(X)$ to be isomorphic. (An answer to this is correct if it lets you prove the next part.)
$(b)$ Prove two equivalence relations $R_1 and R_2$ are isomorphic if and only if the partitions $φ$($R_1$) and $φ$($R_2$) are isomorphic. (Here $φ$ is the bijection from the previous problem.)
(c) Let $X = \{1, 2, 3, 4, 5\}$. Up to isomorphism, how many equivalence relations are there on $X$?
My attempt: As I understand it, equivalence relations can be put in a bijection with partitions, and so if there is a bijection between elements of one relation to another, then there is a bijection between elements of one partition with another. This would make the partitions fit the definition of isomorphism mentioned in the question, therefore proving $(b)$. I do not understand what $(c)$ is asking at all, and I am looking for a formal proof/way to write what I am thinking if what I'm thinking is correct at all.
Hint: notice that with your definition in place two partitions in sets $A_1,..,A_n$ and $B_1,..,B_n$ are isomorphic iff when ordered in ascending order by their number of elements they give the same sequence