https://en.m.wikipedia.org/wiki/Isomorphism My question about module 6 example How is general equation derived (a,b)->(3a+4b) mod 6 I looked at a whole bunch things I am new at this thing According to the example it mentions mod 2 and mod 3 for (a,b) pardon my stupidity shouldn’t it be. (a,b)->(2a+3b) mod 6
Ultimately I would like to derive my own Help
A group isomorphism is a bijective (one-to-one and onto) map from one group to another that respects the group operations. $(a,b)\mapsto(2a+3b) \bmod 6$ is not a bijection, because $(0,0)\mapsto0$ and $(0,2)\mapsto0$, so it can't be an isomorphism.