this question might seem a bit special, but it came up at a crucial point of a proof I read and so I would be very obliged if someone could explain this to me:
given is a smooth projective variety $X$ with canonical sheaf $\omega_X$ and a closed point $x$ on $X$ with residue field $k(x)$. I want now denote with $k(x)$ also the skyskrapersheaf concentrated in $x$ with the field $k(x)$ as stalk.
Now in the proof occurs that one has an isomorphism
$k(x)\simeq k(x)\otimes \omega_X$ in the bounded derived category of coherent sheaves on X, i.e. in $D^{b}(X)$ in the usual notation.
I don't see where this Iso comes from.
Thank you very much!
I think there is a misunderstanding in Grigory's answer:
Fact: If $E$ is invertible and $F$ is a skycraper sheaf then there exists an isomorphism $E\otimes_{O_X} F \simeq F$. (In particular this applies to $E = \omega_X$, $F = k(x)$).
Proof: Just chose a neighborhood $U$ of $x$ and a trivialization $E|_U \simeq O_U$. Then $(E\otimes_{O_X} F)|_U = O_U\otimes_{O_U} F|_U = F|_U$ and extend this isomorphism by the $0$ map outside of $U$.
But this is false if $E$ is locally free of rank $\neq 1$. For example $E = O_X^2$, then $E\otimes F = F^2$ for any $F$ including a skycraper sheaf. Also there is no canonical map $F\to E\otimes F$ in general even if $E$ locally free. You have to chose a local section of $E$ to define such a map.