I am reading group theory (particularly isomorphism) in the algebra, and stuck on a problem. Hope you guys will help me out: Let $G$ be finite group, and $A$,$B$ be normal subgroups of $G$ such that $G=AB$. Prove that $G/(A \cap B)\cong G/A \times G/B$
2026-03-26 19:37:37.1774553857
isomorphism of normal subgroup
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HINT: Use the first isomorphism theorem on the map $$G\ \longrightarrow\ G/A\times G/B.$$ Why is this map surjective?