jacobson radical and frattini

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suppose that $L$ is nilpotent leibniz algebra.why $J(L)=\Phi(L)$.

$J(L)$ is jacobson radical.and $\Phi(L)$is frattini ideal of $L$.and we know that if $L$ is nilpotent $L^2=\Phi(L)$.

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In a nilpotent Leibniz algebra L every maximal subalgebra of L is an ideal of L (see D.W.Barnes, Some theorems on Leibniz algebras, Comm. In Alg. 39. , 2011, 2463-2472).