Jordan form of a real matrix with distinct complex eigenvalues

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Someone please shed some light to my confused brain: "The statement says that a 4 by 4 real matrix B has 4 eigenvalues $\alpha, \bar{\alpha}, -\alpha, -\bar{\alpha}$ where $\alpha = a+ib$, $a,b$ both not zero. Then it is obvious that the Jordan form of B is diagonal."

My question: Does this mean diagonal in the literal sense? Or should it look like J1 + J2, where

  • J1(1,1)= a, J1(1,2)= b, J1(2,1)=-b, J1(2,2)=a

  • J2(1,1)=-a, J2(1,2)=-b, J2(2,1)=-a, J2(2,2)=b

  • $+$ means direct sum.