Jordan normal form of $ A + \alpha I$

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Help me please,

I tried to prove, that JNF of matrix $ A + \alpha I$ is equal to matrix $ A_j + \alpha I$ where $A_j$ is JNF of A.

Is it true, that $ A_j + \alpha I$ - JNF by definition? Because, it is block diagonal matrix and every block are Jordan blocks.

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If $S^{-1}AS=B$ then $S^{-1}(A+\alpha I)S=S^{-1}AS+S^{-1}\alpha I S=B+\alpha I$.

If $B$ is the Jordan canonical form of $A$, then by inspection $B+\alpha I$ is in Jordan canonical form, and hence is the Jordan canonical form of $A+\alpha I$.