Kronecker product, matrices

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Let $\mathbb{I}_{3}$ be the $3\times 3$ identity matrix, i. e.

$\begin{pmatrix} 1 &0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{pmatrix}$

and $e_1:=\begin{pmatrix} 1 \\ 0 \end{pmatrix}$, $e_2:=\begin{pmatrix} 0 \\ 1 \end{pmatrix}$.

My question is, if the matrix $(\mathbb{I}_{3}\otimes e_1,\mathbb{I}_{3}\otimes e_2) $ is the same as $\mathbb{I}_{3}\otimes \mathbb{I}_{2}$? I have illustrated it, but do not know how to write this down mathematically.

$A\otimes B=\begin{pmatrix} a_{11} B & a_{12} B \\ a_{21} B & a_{22} B \end{pmatrix}$

It is

$(\mathbb{I}_3 \otimes e_1,\mathbb{I}_3 \otimes e_2)= \begin{pmatrix} \begin{pmatrix} 1 \\ 0 \end{pmatrix} & 0 & 0 \\ 0 & \begin{pmatrix} 1 \\ 0 \end{pmatrix} & 0 \\ 0 & 0 & \begin{pmatrix} 1 \\ 0 \end{pmatrix} \end{pmatrix}, \begin{pmatrix} \begin{pmatrix} 0 \\ 1 \end{pmatrix} & 0 & 0 \\ 0 & \begin{pmatrix} 0 \\ 1 \end{pmatrix} & 0 \\ 0 & 0 & \begin{pmatrix} 0 \\ 1 \end{pmatrix} \end{pmatrix}$

But i don’t see in it $\mathbb{I}_{3}\otimes \mathbb{I}_{2}$.