Lambert series and higher order derivatives of the Euler Function

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It is well known that:

$$\sum_{n=1}^\infty \frac{n q^n}{1-q^n} = -q \frac{d}{dq} \Phi(q)$$

Where $\Phi$ is defined as follows for $|q|<1$:

$$\Phi(q) = \prod_{n=1}^\infty (1-q^n)$$

  1. Is there any similar expression that showcases any type of relationship between $\Phi(q)$ and:

$$\sum_{n=1}^\infty \frac{q^n}{1-q^n}$$

?

  1. Is there any related result (expressing the Lamber series in terms of $\Phi$) for an integer $\alpha > 1$ in:

$$\sum_{n=1}^\infty \frac{n^\alpha q^n}{1-q^n}$$

?

Thank you in advance.