How does one solve for $x$ in a polynomial of the form $ax^{n} + bx^{\left(n - 1\right)} + c = 0$, given that $n$ is a larger number ?. For example:
$\displaystyle x^{100} - 3x^{99} + 1 = 0$
How does one solve for $x$ in a polynomial of the form $ax^{n} + bx^{\left(n - 1\right)} + c = 0$, given that $n$ is a larger number ?. For example:
$\displaystyle x^{100} - 3x^{99} + 1 = 0$
I'm still not sure I understand the question, but this is easy with a computer, assuming you want numerical values. I wrote a python script to do this. (Annoyingly, numpy expects the leading coefficient $x^k$ of a polynomial of degre $n$ to be at index $n-k.$)
produces this output instantaneously:
Is there some reason that this isn't good enough?