Find largest possible integer n such that $1!+2!+3!+... +n! =m^2$.
I can kind of guess the answer is 3, but I don't know how to get it. What's the first step in this question? Thanks.
Find largest possible integer n such that $1!+2!+3!+... +n! =m^2$.
I can kind of guess the answer is 3, but I don't know how to get it. What's the first step in this question? Thanks.
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