Use the laws of sets to prove:
a. $ C- [A^{c} ∪ (A ∪ B)^{c}]^{c} = C ∩ A^{c} $
I am struggling regarding how to prove this.
De Morgan's Law: $ C- [A^{c} ∪ (A^{c} ∩ B^{c})]^{c} $
Distributive Law: $ C- [(A^{c} ∪ A^{c}) ∩ (A^{c} ∪ B^{c})]^{c} $
Idempotent Law: $ (A^{c} ∪ A^{c}) = A^{c} $
$ C- [(A^{c}) ∩ (A^{c} ∪ B^{c})]^{c} $
Are my workings so far correct? I would appreciate any assistance in how to proceed in proving this.
You did well so far. As L KM wrote in the comment, you can use absorption law $X\cap (X\cup Y)=X$ and choose $X=A^C$ and $Y=B^C$. Then, you are almost done.
Remark: You can do is even shorter. Use the other absorption law $X\cup (X\cap Y)=X$ with $X=A^C$ and $Y=B^C$ right after your first step.