LCM of two periodic signals,

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Why is $$\text{lcm}\left(\frac{\pi}{5},\frac{\pi}{2}\right)=\pi$$ where the $10$ here represents the period of $2\cos(10t+1)-\sin(4t-1)$

where $\displaystyle\frac{\pi}{5}$ is the period of $2\cos(10t+1)$ and $\displaystyle\frac{\pi}{2}$ is the period of $-\sin(4t-1)$.

The question is not why the lcm but it's why does the lcm of these two give $\pi$.

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Suppose $n\pi/5=m\pi/2$ where $n,m\in\Bbb Z_{>0}$. For least multiple we need to minimize $m$. We get $n/m=5/2$ and the minimum $m$ that gives $n$ integral is $m=2$.

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$$LCM(\frac{a}{b},\frac{c}{d},\frac{e}{f})=\frac{LCM(a,c,e)}{HCF{(b,d,f)}}.$$