Could someone tell me how to show $$\left|\frac{e^{z}-1}{z}\right| \leq 1,$$ for $\text{Re}(z) \leq 0$?
I can see the function is bounded, but I am unable to show this is bounded by $1$. Any help would be appreciated. Thanks in advance.
2026-04-01 23:14:20.1775085260
$\left|\frac{e^{z}-1}{z}\right| \leq 1$, for $\text{Re}(z) \leq 0$?
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