Let $a, b$ integers such that $ab+2a+3b=93$. Find all solutions integers.
What I tried is $ab+2a+3b=b(a+3)+2a$ but i don't see how to proceed to related $a$ and $b$ such that see it multiplying and play with combinations of $93=3*13$.
2026-04-01 02:48:30.1775011710
Let $a, b$ integers such that $ab+2a+3b=93$. Find all solutions integers.
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$(a+3)(b+2)=99$
then you can decompose 99 and get integer solutions.