Let $f_n$ uniformly convergent to$ f$. Proof that $f$ is integrable and $\int_A f_n \rightarrow \int_A f$

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(When I write integrable I mean Riemann-integrable)

Let $A \subseteq \mathbb{R}^m$ be a block, $f_n:A\rightarrow R$ be integrable functions and $f_n \rightarrow_{un} f$. Proof that $f$ is integrable and $\int_A f_n \rightarrow \int_A f$

I tried to use here the Lebesgue Criterion. (http://www.math.ncku.edu.tw/~rchen/Advanced%20Calculus/Lebesgue%20Criterion%20for%20Riemann%20Integrability.pdf)

Since each $f_i$ is integrable, the set of discontinuities of each $f_i$ has measure $0$. Since the convergence is uniform, the set of discontinuities of $f$ will also have measure $0$, then $f$ is integrable. My "proof" is just a sketch, I believe it's needing formalization, but I'm not sure how to do it. I'm also not sure how to analyse the sequence of the integrals either.

Can someone help me? Thanks.

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Remember that: $f$ is integrable on $A$ iff, for every $\varepsilon>0$, there exists a partition $P$ of $A$, such that $$ U(f,P)-L(f,P)<\varepsilon $$ where $L(f,P)$, $U(f,P)$ are the lower and upper sums of $f$ corresponding to $P$.

Let now $\varepsilon>0$. Since $f_n\to f$ uniformly on $A$, there exists an $N\in\mathbb N$, such that $n\ge N$, implies that $$ \sup_{x\in A}\lvert\, f_n(x)-f(x)\rvert<\frac{\varepsilon}{2(\mu(A)+1)}, $$ where $\mu(A)$ is the volume of $A$. Let $P$ a partition of $A$ for which $U(f_N,P)-U(f_N,P)<\frac{\varepsilon}{2}$. Note that, the partition $P$ divides $A$ in $K$ sub-blocks $\varDelta A_1,\ldots,\varDelta A_K$ of volumes $\mu(\varDelta A_1),\ldots,\mu(\varDelta A_K)$, respectively, and set $M_j(\,f_N),m_j(\,f_N)$ be the supremum and infimum of $f_N$ in $A_j$. Then $$ L(\,f_N,P)=\sum_{j=1}^K \mu(A_j)\,m_j(\,f_N), \quad U(\,f_N,P)=\sum_{j=1}^K \mu(A_j)\,M_j(\,f_N) $$ and $$ \lvert m_j(f_N)-m_j(f)\rvert < \frac{\varepsilon}{2(\mu(A)+1)},\,\,\, \lvert M_j(f_N)-M_j(f)\rvert < \frac{\varepsilon}{2(\mu(A)+1)} $$ and hence $$ U(f,P)-L(f,P)\le \cdots \le \frac{\varepsilon}{2}+\frac{\varepsilon \mu(A)}{2(\mu(A)+1)}<\varepsilon. $$ ETC