$(a)$ ${rank}(PQ)=n$
$(b)$ $rank (QP)=m$
$(c)$ $rank(PQ)=m$
$(d)$ $rank(QP)=k$ , where $k$ is the smallest integer value of $\frac{m+n}{2}$.
This is not a homework , it is asked in my exam today.
$(a)$ ${rank}(PQ)=n$
$(b)$ $rank (QP)=m$
$(c)$ $rank(PQ)=m$
$(d)$ $rank(QP)=k$ , where $k$ is the smallest integer value of $\frac{m+n}{2}$.
This is not a homework , it is asked in my exam today.
In order for $PQ$ or $QP$ to even make sense, you would have to have $m=n$. Then these are square $m\times m$ (or $n \times n$, same thing) matrices. Also note that then $\frac{m+n}{2}=\frac{m+m}{2}=m$. Is it possible for $PQ$ and $QP$ to have rank $m$?