The question: Let $R$ be a ring and $I$ be an ideal of $R$. Is it true that if $R$ is not an integral domain then also $R/I$ isn't an integral domain?
My attempt at solution is the following:
I don't think the claim is true. As a counterexample I take $R=6\mathbb{Z}$ and $I=2\mathbb{Z}$ I believe that $R/I=3\mathbb{Z}$ which is an integral domain, while $R$ isn't an integral domain since it has zero divisors.
I am not sure, if I got it right.
Any help?
Thanks!
Choose, $R=\Bbb{Z_6}$ and $I =\{0, 3\}$
Now, $R/ I \cong Z_3$ which is an integral domain.
Hence, $R/ I$ integral domain doesn't imply $R$ is an integral domain.