The six sets $A_1, \ldots, A_6$ each contain $4$ elements. The $n$ sets $B_1, \ldots, B_n$ each contain $2$ elements. Let $S = A_1 \cup A_2 \cup \cdots \cup A_6 = B_1 \cup B_2 \cup \cdots \cup B_n$. Each element of $S$ belongs to exactly four of the sets $A_1, \ldots, A_6$ and exactly three of the sets $B_1, \ldots, B_n$. Find $n$.
2026-04-13 17:27:45.1776101265
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Let $S = A_1 \cup A_2 \cup \cdots \cup A_6 = B_1 \cup B_2 \cup \cdots \cup B_n$. Find $n$ if each element of $S$ belongs to four $A$s and $3$ $B$s.
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Strategy:
- Given that the $6$ sets $A_1, \ldots, A_6$ each contain $4$ elements, how many elements would there be in their union if they were disjoint?
- Given that each element of $S$ belongs to exactly $4$ of the $6$ sets $A_1, \ldots, A_6$, how many elements are in $S$?
- Given that the $n$ sets $B_1, \ldots, B_n$ each contain $n$ elements, how many elements would there be in their union if they were disjoint?
- Given that each element of $S$ belongs to exactly $3$ of the $n$ sets $B_1 \ldots, B_n$, how many elements are in the union?
- Equate the results of steps 2 and 4 to solve for $n$.
Say $S =\{1,2,3,...,k\}$. Then $S = A_1 \cup A_2 \cup \cdots \cup A_6$ we have $$6\cdot 4 = k\cdot 4 \implies k=6$$
From $S = B_1 \cup B_2 \cup \cdots \cup B_n$ we have $$n\cdot 2 = k\cdot 3\implies n = 9$$