Let $W_{1},W_{2}$ be linear sub-spaces of $\mathbb{R}^{4}$.
$W_{1}=\text{sp}\{(1,2,3,4),(3,4,5,6),(7,8,9,10)\}$
$W_{2}=\text{sp }\{(x,y,z,w)| \ x+y=0\}$
Find a linear subspace of $ \ \mathbb{R}^{4} \ ; W_{3}$ , such that: $W_{3}\subset W_{2} \ \text {*and*} \ W_{1}\oplus W_{3}=W_{1}+W_{2}$
My attempt:
I applied Gaussian elimination on the vectors of $W_1$, such that:
$$W_{1}=\left\{ \left(\begin{array}{c} x\\ y\\ z\\ w \end{array}\right)=a\left(\begin{array}{c} 1\\ 0\\ -2\\ -1 \end{array}\right)+b\left(\begin{array}{c} 0\\ 1\\ -2\\ -1 \end{array}\right)|a,b\in\mathbb{R}\right\} $$
At that point I got stuck. I'm not sure how to continue.
HINT
We should write as a span (check again you derivation by RREF)
$$W_{1}=\left\{ \left(\begin{array}{c} x\\ y\\ z\\ w \end{array}\right)=s\left(\begin{array}{c} 1\\ 1\\ 1\\ 1 \end{array}\right)+t\left(\begin{array}{c} 0\\ 1\\ 2\\ 3 \end{array}\right)\right\}$$
and we can also easily find that
$$W_{2}=\left\{ \left(\begin{array}{c} x\\ y\\ z\\ w \end{array}\right)=r\left(\begin{array}{c} 1\\ -1\\ 0\\ 0 \end{array}\right)+s\left(\begin{array}{c} 0\\ 0\\ 1\\ 0 \end{array}\right)+t\left(\begin{array}{c} 0\\ 0\\ 0\\ 1 \end{array}\right)\right\}$$
then check by RREF on the $5$ basis vectors that $W_{1}+W_{2}$ has dimension $4$ and finally select 2 basis vectors for $W_3$ from the basis vectors of $W_2$ such that $W_{1}\oplus W_{3}=\mathbb{R^4}$.