Show that $\textbf{v} + W \subseteq W \Rightarrow W \subseteq \textbf{v} + W.$
Here is my proof, is it correct? Is there any easier way?
Note that for any element $\mathbf{v + w}$ in $v+W$, $\mathbf{v+w}$ is in $W$ as well. Hence $\mathbf{v} + \mathbf{w} = \mathbf{w}_{1}$ for some $\mathbf{w_1} \in W$ Which implies $\mathbf{v} = \mathbf{w}_{1} -\mathbf{w} \in W$
Now the proper proof starts :
Let $w_2 \in W$, now $ \mathbf{w}_{2} - \mathbf{v} = \mathbf{w}_{2} - (\mathbf{w}_{1}-\mathbf{w}) = \mathbf{w}_{3}$ for some $\mathbf{w}_{3}$. Hence $\mathbf{w}_{2} = \mathbf{v} + \mathbf{w}_{3} \in \mathbf{v} + W$. Thus $ W \subseteq \mathbf{v} + W$.
I don't understand your proof. You start with “Let $y\in\mathbf{v}+W$”, but what you should be proving is that $W\subset\mathbf{v}+W$, assuming that $\mathbf{v}+W\subset W$. Therefore, the proof should start with “Let $y\in W$”.
I would prove it as follows: since $\mathbf{v}+W\subset W$, $\mathbf{v}\in W$, because $\mathbf{v}=\mathbf{v}+0\in\mathbf{v}+W\subset W$. But then, since $W$ is a subspace, $\mathbf{v}+W\subset W$.
If you want to prove the reverse implication, it's similar. If $W\subset\mathbf{v}+W$, then $0=\mathbf{v}+\mathbf{w}$, for some $\mathbf{v}\in W$. Therefore, $\mathbf{v}=-\mathbf{w}\in W$, which implies that $\mathbf{v}+W\subset W$.