Limit as $x\to \infty$ of $3(x^a) - 2(x^a)$

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I'm not sure what this limit should equal. Same goes for the equation where $a$ is equal to $1$. I want to say that it should equal the difference of the multipliers (1), but I'm not sure.

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HINT

Note that

$$3x^a-2x^a=x^a$$

then we need to consider the following cases

  • $a>0$
  • $a=0$
  • $a<0$