Limit $\lim_{x\to 0}\frac{\sin\left(\pi\cos^2(x)\right)}{x^2}$

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Could someone help me solve this limit without L'Hopital's rule? $$ \lim_{x\to 0}\frac{\sin\left(\pi\cos^2(x)\right)}{x^2} $$

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Use the identity $\sin(x)=\sin(\pi-x)$ and then multiply and divide by the argument of $\sin$.