limit of a fundemental solution

Question

Is it possible and how can I calculate the limit of $$\\lim_{t \downarrow 0}v(t,x)=t^\frac{-3}{2}e^\frac{-|x|^2}{4t}$$ when $x \in \mathbb{R}^3$ and $t>0$? For sure, it's not continuous at 0, so I can't just plug in 0.