Limit of floor function and sqrt

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Is anyone able to help me with the following limit question $$\lim_{x \to +\infty} \frac{ \left\lfloor \sqrt{x} \right\rfloor }{ \sqrt{x} } $$

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Hint: use the fact that for any $y$, $y - 1 < \lfloor y \rfloor \le y$.