Limit​ without L'hopital or series

Question

$\lim_{x \to 0}\frac{e^x-1}{x}$.

I thought of designing a function and using sandwich theorem but couldn't find anything

Edit

Is there any algebric way to solve the limit? For example we can solve the limit

(Sinx-x)/x x tending to 0 by replacing x by 3y where y tends to 0

Answer 1

This is just the derivative of $e^x$ at $x=0$ and therefore the limit is $1$.