$$\lim_{z \to i} \frac{z^4-1}{z-i}$$
I'm reading in a bunch of places that I can't use L'Hopital's rule for this problem. Why is this so? And if I can't use this rule then how would I go about solving this? Using the rule resulted in $\lim = -i$
2026-04-04 04:36:29.1775277389
Limits and L'Hopital
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Hint:
$$z^4-1=(z^2-1)(z^2+1)=(z+1)(z-1)(z+i)(z-i)$$