I came across this particular question on my maths textbook while I was revising for my exams.
My solution for the question is 1, and Photomath said:
$x$ is negative since $x$ approaches negative infinity
I can’t find any examples on the book that explains the problems, so now I am reaching out for help here for an explanation for this. Thanks!
P.S I have no idea of the code for displaying an equation, so both the question and the correct solution were uploaded as an image
It is -1 since the numerator is positive (Since the leading term is $3|x|$) and the denominator approaches -$\infty$ which is negative and a positive divided by a negative is always negative even in the limit.