Line integral between curve generated by intersection of a plane and surface

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$$\int_D (xy)\mathrm{d}x-x^2\mathrm{d}y+z\mathrm{d}z$$ where $D:\ x^2+y^2-4z^2=1 ; z=1$

I can't seem to figure out how to make the figure nor what are the parametrics, I thought they would be: $x(t)=\sqrt5\cos t ; y(t)=\sqrt5\sin t ; z(t)=1$ where $t \in[0,2\pi]$ I think.

I should be able to solve this problem after I learn how to figure these 2 things out, any help is much appreciated!

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Ok, I am guessing you mean that you are cofined to move in the circular cross section of the surface and plane $z=1$. We can get the cross section by plugging $z=1$ into the surface's equation:

$$ x^2 + y^2 = 5$$

Returning to line integral:

$$ \int_D (xy)dx - x^2 dy + z dz$$

Note that since we don't move in the z direction, the last integral is zero. This leads to:

$$ \int_D (xy)dx - x^2 dy $$

After this you can parameterize as with $ x =\sqrt{5} \cos(t) $ and $y= \sqrt{5}\sin(t)$