$$\int_C yz^2\,ds$$
$x = 4t,\,y = 3\sin t,\,z = 3\cos t,\\0\leq t\leq\frac\pi2$
I know how to take integrals like this, but the function is of $y$ and $z$. I usually see them in terms of $x$ and $y$, where $z=f(x,y)$.
In this question, is $x= f(y,z)$ and is the $x = 4t$ a bit of a red herring?
I've setup the integral below. Thanks
$$\int_C 3\sin t\times 9 \cos^2t\,ds$$
where $$ds = \sqrt{\left(\frac{dy}{dt}\right)^2*\left(\frac{dz}{dt}\right)^2}\, dt$$