Linear Algebra: How to prove that $AC^T$ is a diagonal matrix

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How would I prove that the product of a $n \times n$ matrix $A$ and its adjugate matrix $C^T$ (transpose of cofactor matrix $C$) $AC^T$ is diagonal ($AC^T$=$det(A)I$)? I've attempted to use cofactors and the fact that any non-diagonal element of $AC^T$ is the product of a cofactor and an element that shares a row with the elements of the cofactor, but I don't know where to go from there. Help is greatly appreciated!

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Hint: Each entry of $AC^T$ is the Laplace expansion of the determinant of some matrix. For the off-diagonal entries, this matrix has a repeated row.