Linear Algebra: links between rank and characteristic polynomial

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Question:

The characteristic polynomial of a square matrix B is given as $t^2(t^2+1)$. From this information, deduce all the possible values of rank($B^2$)

Here is my attempt so far:

The degree of the characteristic polynomial p(t)=4. The eigenvalues are 0, $\pm i $. The rank corresponds to the number of non-zero eigenvalues.

My confusion starts here, since the eigenvalues are complex.

I would appreciate any help with this question. Thank you.

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Well in general it holds that rank$(AB) \leq$ min$($rank$(A), rank(B)$) so in your case we get:

rank$(A^2) \le $rank$(A)$. From here it quickly follows that rank$(A)=1$ or $2.$

From here you can probably figure out the rest.