Intuitively it means that, when combined with the other equations, they provide the same information. More rigorously, it means that there is some "linear combination" of the equations which gives $0=0$.
This is easiest to see when, as in your case, you have $n$ equations and $n-1$ of them are redundant; this means that each one is a scalar multiple of the other.
6
Bumbble Comm
On
Since $\det(A-\lambda I) = 0$, $A-\lambda I$ is singular and therefore not full (row) rank. Therefore some equations can be written into a linear combination of others, and those equations are considered to be "redundant", as they give no additional information about the solutions.
0
Bumbble Comm
On
It means that you don't need them to solve the system. The other equations gave you already all the information you needed, thus they are redundant.
Intuitively it means that, when combined with the other equations, they provide the same information. More rigorously, it means that there is some "linear combination" of the equations which gives $0=0$.
This is easiest to see when, as in your case, you have $n$ equations and $n-1$ of them are redundant; this means that each one is a scalar multiple of the other.