In the set $V=\{x|x\in \mathbb R,x>0\}$, I know it is not closed under multiplication. But I am not sure how to prove or make counterexample in the addition property. Can anyone help explain this to me?
2026-04-29 11:03:40.1777460620
Linear Algebra: Vector Space (non example)
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as this set isn't closed under addition (there exists no inverse elements $y$ such that for every $x: x+y =0$), then it is not a vector space