Let $f: \mathbb{C}^5 \to \mathbb{C}^5 $ a linear transformation such that $f^3$ is diagonalizable, but $f^2$ is it not.
Is it true that $f$ necessarily has a $3 \times 3$ jordan block with a null diagonal?
2026-04-01 19:03:40.1775070220
Linear transformation with diagonalizable power
90 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in LINEAR-ALGEBRA
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