I have the following question and answers:
Let $A = \{1,2,3,4\}$. Write down $R \subseteq A x A$ which has one of the three properties of an equivalence relation (3 cases).
The official answers for the above are (taken from textbook):
Case 1: Only reflexive
$R_1 = \{(1,1), (2,2), (3,3), (4,4), (1,2), (2,3)\}$
My question: Is it necessary to include (1,2) and (2,3) here? Can I not include other pairs such as (1,4) and (2,4) in order to ensure this is just reflexive?
Case 2: Only symmetric
$R_2 = \{(1,2), (2,1)\}$
My question: Do I really have to use (1,2) and (2,1) here? Can I not use (3,1), (1,3) which is inside the A x A?
Case 3: Only transitive
$R_3 = \{(1,1), (1,3)\}$
My question: Similar to symmetric, must do I really have to use (1,1) and (1,3)? Can I show this is transitive using (1,2) and (2,3) - since (1,3) is also in AxA.
The reason why I am confused is because I thought the available pairs for this AxA is
Hence I should be able to pick any pairs there as long as it fulfill the requirement of the question?

Change the names of the elements of $A$. Say $A=\{a,b,c,d\}$. For instance, the answer to case 2 now is $\{(a,b),(b,a)\}$. It is clear that the change of names do not change essentially anything?
Now change again:
$$A=\{1,3,2,4\}.$$
How is now changed case 2? Has this solved your question to case 2?
This not directly solves your other questions, but I hope make you walk for the right path.