A is a given point and P is any point on a given straight line. If AQ=AP and AQ makes a constant angle with AP find the locus of Q.
According to me the answer should be two straight lines making angle equal to ±x(angle between AQ and AP) with line on which P moves at P and Q of the only triangle whose Q is on the line on which P moves. These two lines intersect at the image of A with respect to line on which P moves. Just need to confirm it and get a decent looking solution. I did on Geogebra and I get this.
I used 45 degrees as the given angle here.