does any body have information about below polytope?
Suppose we have 6 points in $\mathbb{R^{6}}$:
$(1,1,1,0,0,0),(0,1,1,1,0,0),(0,0,1,1,1,0),(0,0,0,1,1,1),(1,0,0,0,1,1),(1,1,0,0,0,1)$
what is convex-hull of these points?
I have these information:
1-Since the vertices are not affinely independent it is not simplex.
2-this is a 3-dimension polytope.
I need more information about the geometry of this polytope! number of facets? and more important is it a famous 3D shape?
Just calculate the distances between adjacent points. Those would be $\sqrt{2}$.
Next calculate the distances between one but adjacent ones. Those will be $\sqrt{4}=2$.
Finally calculate the distances between opposites (wrt. the given cycle). Those are $\sqrt{6}$.
That is, these length are in ratio $1:\sqrt{2}:\sqrt{3}$, which are well-known distances within a cube. In fact, you just described a non-planar hexagon, the Petrie polygon of the cube.
Alternatively, you could consider the hull of that Petrie polygon. Then this would be a narrow trigonal antiprism. The lacing triangles of which are diagonally divided squares. I.e. the large regular base triangles have sides with a factor $\sqrt{2}$ larger than the lacing edges.
You even could consider this figure as being a cube, when placed axially along its body diagonal, and having chopped off both its polar segments (pyramids).
--- rk